10-29x+21x^2=0

Solution for 10-29x+21x^2=0 equation:

10-29x+21x^2=0

a = 21; b = -29; c = +10;
Δ = b2-4ac
Δ = -292-4·21·10
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1}=1$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-29)-1}{2*21}=\frac{28}{42}
=2/3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-29)+1}{2*21}=\frac{30}{42}
=5/7
$